KEMBAR78
Wind energy | PPTX
Chapter 7
Wind energy
By: MESFIN MEGRA.
WIND POWER – WHAT IS IT?
All renewable energy (except tidal and
geothermal power), ultimately comes from the
sun.
The earth receives 350 W/m2 from the sun.
About 2% of this energy (= 7 W/m2) is
converted to wind energy. 12/19/2017
2
WIND POWER – WHAT IS IT? Cont....
Differential heating of the earths surface and
atmosphere induces vertical and horizontal air
currents that are affected by the earth’s
rotation and contours of the land.
12/19/2017
3
Uneven heating:
Intensity of solar energy is varies due to the
angle of the sun (the equator vs the poles).
Land heats up faster than water does, but also
loses heat faster.
These difference in air temperature across the
globe can create wind. 12/19/2017
4
Uneven heating: Con….
35% of wind energy (2.45 W/m2) is dissipated
in the first kilometers above the Earth’s surface
and available for turbine.
12/19/2017
5
Available power:
Over a period of one year, the wind energy (E) is
approximately.
𝐸 = 𝑖𝑛𝑡𝑒𝑛𝑠𝑖𝑡𝑦 ∗ 𝐸𝑎𝑟𝑡ℎ′
𝑠 𝑆𝐴 ∗ 𝑆𝑒𝑐𝑜𝑛𝑑𝑠 𝑝𝑒𝑟 𝑦𝑒𝑎𝑟
= 2.45 𝑊/𝑚2 5.1 𝑥 1014
𝑚2
3.2 𝑥 107
𝑠
= 4.0 𝑥 1022
𝐽
Which is 200 times larger than our energy
consumption (2.0 𝑥 1020
𝐽). 12/19/2017
6
Maximum Power Extracted
Calculate the power extracted from wind.
Calculate kinetic energy, 𝐾𝐸 =
1
2
𝑚𝑣2 of air
passing through the rotor of the wind turbine.
Measure mass of the air travelling through area
of circle swept out by rotor blades in time ∆𝑡.
12/19/2017
7
Con….
Time t = 0:
Time ∆𝑡:
𝑣. ∆𝑡
Figure 1: At time t=0, mass of air is just about to pass through the loop, but
∆𝑡 later, the mass of air is passed through the loop. The mass of this piece of
air is the product of its density 𝜌, area A, and length 𝑣. ∆𝑡.
A
12/19/2017
8
Con….
From this you can find the mass.
M𝑎𝑠𝑠 = 𝑑𝑒𝑛𝑠𝑖𝑡𝑦 ∗ 𝑣𝑜𝑙𝑢𝑚𝑒
= 𝜌 ∗ 𝐴 ∗ 𝑣 ∗ ∆𝑡
𝑣 𝑖𝑠 𝑡ℎ𝑒 𝑣𝑒𝑙𝑜𝑐𝑖𝑡𝑦 𝑜𝑓 𝑎𝑖𝑟
𝜌 𝑖𝑠 𝑑𝑒𝑛𝑠𝑖𝑡𝑦 𝑜𝑓 𝑎𝑖𝑟 1.23 𝑓𝑜𝑟 𝑠𝑡𝑎𝑛𝑑𝑎𝑟𝑑 𝑇 𝑎𝑛𝑑 𝑃
∆𝑡 𝑖𝑠 𝑙𝑒𝑛𝑔𝑡ℎ 𝑜𝑓 𝑡𝑖𝑚𝑒 𝑓𝑜𝑟 𝑎 𝑢𝑛𝑖𝑡 𝑎𝑖𝑟 𝑡𝑜 𝑝𝑎𝑠𝑠 𝑡ℎ𝑟𝑜𝑢𝑔ℎ
𝐴 𝑖𝑠 𝑎𝑟𝑒𝑎 𝑠𝑤𝑒𝑝𝑡 𝑏𝑦 𝑡ℎ𝑒 𝑏𝑙𝑎𝑑𝑒𝑠, 𝑛𝑜𝑡 𝑡ℎ𝑒 𝑏𝑙𝑎𝑑𝑒 𝑎𝑟𝑒𝑎
12/19/2017
9
Con….
Therefore the kinetic energy, KE, is found to be.
𝐾𝐸 =
1
2
𝑚𝑣2 =
1
2
𝜌𝐴∆𝑡𝑣3
While the power of the wind passing through the
loop is.
𝑃 =
1
2
𝜌𝐴∆𝑡𝑣3
∆𝑡
=
𝟏
𝟐
𝝆𝑨𝒗 𝟑
12/19/2017
10
Con….
But turbines can’t extract all of the kinetic energy
of the wind.
Why not?
The above expression is true for a single wind
turbine in constant wind condition.
12/19/2017
11
Actual Power Extracted from the Wind
The actual power extracted by the rotor blades is
the difference between the upstream and the
downstream wind powers.
𝑃 𝑜
=
1
2
𝑚𝑎𝑠𝑠 𝑓𝑙𝑜𝑤 𝑟𝑎𝑡𝑒 𝑝𝑒𝑟 𝑠𝑒𝑐𝑜𝑛𝑑 . (𝑉2
− 𝑉𝑜
2
)
𝑉 = 𝑢𝑝𝑠𝑡𝑟𝑒𝑎𝑚 𝑤𝑖𝑛𝑑 𝑣𝑒𝑙𝑜𝑐𝑖𝑡𝑦
𝑉𝑜= 𝑑𝑜𝑤𝑛𝑠𝑡𝑟𝑒𝑎𝑚 𝑤𝑖𝑛𝑑 𝑣𝑒𝑙𝑜𝑐𝑖𝑡𝑦
𝑃𝑜 = 𝑚𝑐ℎ𝑎𝑛𝑖𝑐𝑎𝑙 𝑝𝑜𝑤𝑒𝑟 𝑜𝑢𝑡𝑝𝑢𝑡 12/19/2017
12
Con….
The mass flow rate of air through the rotating
blades is, therefore, derived by multiplying the
density with the average velocity. That is
M𝑎𝑠𝑠 𝑓𝑙𝑜𝑤 𝑟𝑎𝑡𝑒 = 𝜌. 𝐴.
𝑉 + 𝑉𝑜
2
12/19/2017
13
Con….
The mechanical power extracted by the rotor,
which is driving the electrical generator is
therefore:
𝑃𝑜 =
1
2
𝜌. 𝐴.
𝑉 + 𝑉𝑜
2
. (𝑉2
− 𝑉𝑜
2
)
12/19/2017
14
Con….
The above expression can be algebraically
rearranged:
𝑃𝑜 =
1
2
𝜌. 𝐴. 𝑉3
.
1 +
𝑉𝑜
𝑉
1 −
𝑉𝑜
𝑉
2
2
12/19/2017
15
Con….
The power extracted by the blade is customarily
expressed as a fraction of the upstream wind power
as follows:
𝑃𝑜 =
1
2
𝜌. 𝐴. 𝑉3
. 𝐶 𝑝
where
𝐶 𝑝 =
1 +
𝑉𝑜
𝑉
1 −
𝑉𝑜
𝑉
2
2
12/19/2017
16
Con….
For a given upstream wind speed, the value of Cp
depends on the ratio of the downstream to the
upstream wind speeds that is
𝑉𝑜
𝑉
.
The plot of power coefficient versus (
𝑉𝑜
𝑉
) shows that Cp
is a single, maximum value function
12/19/2017
17
Con….
It has a maximum value of 0.59 (Betz limit) when the
( 𝑉𝑜
𝑉) is one-third (0.33).
The maximum power is extracted from the wind at
speed ratio, when the downstream wind speed equals
one-third of the upstream speed.
𝑃𝑚𝑎𝑥 =
1
2
𝜌. 𝐴. 𝑉3
. 0.59 12/19/2017
18
Con….
The theoretical maximum value of Cp is 0.59. in
practical designs, the maximum achievable Cp is below
0.5.
12/19/2017
19
Efficiency
Wind turbines are not 100% efficient.
Power = efficiency * max. power extracted
𝑃𝑜 = 𝜂
1
2
𝜌. 𝐴. 𝑉3
= 𝜂
1
2
𝜌. 𝑉3
. 𝜋
𝑑
2
2
=
1
8
𝜂. 𝜌. 𝑉3
. 𝜋𝑑2 12/19/2017
20
Factor affecting wind power harnessing
The power produced by a wind turbine depends
on:
Rotor area
Air density
Wind speed
Wind shear 12/19/2017
21
Con….
Wind shear is a difference in wind speed and direction
over a short distance and is caused by mountains,
coastline, and weather pattern.
Air density increases with colder temperatures,
decreased with altitude, and decreased humidity
Wind speed increases the farther you get away from
ground. 12/19/2017
22
Con….
As you get higher off the ground, the air speed
increases. The rotor are tilted slightly upwards so that
each part of the rotor is exposed to the same speed
12/19/2017
23
Con….
Wind turbines are most efficient when wind
moves uniformly in the same direction.
Turbulence is caused by buildings, trees, and land
formations (wind break).
The edge of a continental shelf, high ground and
tundra have low turbulence and are the best
locations to build a turbine
12/19/2017
24
Feasibility
Local wind speed is also an important factor
since power ∝ (𝑤𝑖𝑛𝑑 𝑠𝑝𝑒𝑒𝑑)3
.
The local wind speed should be, on average, at
least 7 m/s at 25 m above the earth’s surface in
order to make harnessing wind from it
worthwhile. 12/19/2017
25
Demand and Dependability
Wind is not locally predictable in the short term,
and so its use should be limited to only fulfill 5-
15% of the total energy demand of the area.
Setting up turbines in several locations makes
wind energy more reliable.
12/19/2017
26
Con….
The available power is averaged.
Globally there is always a relatively constant
amount of wind energy being harnessed at any
one moment.
12/19/2017
27
Configuration of Wind Turbine
12/19/2017
28
HAWT’s vs VAWT’s
HAWT’s
Advantage
Variable pitch
Tall tower- higher
wind speeds
Steady angle attack
Disadvantage
Tall tower/large blade-
difficult to install
High visibility
Yaw control is necessary
12/19/2017
29
HAWT’s vs VAWT’s cont.…
VAWT’s
Advantage
Smaller support
structure
Yaw control not needed
Generator components
located on the ground
Less noise compared to
HAWT’s
Disadvantage
Cyclic loading makes fatigue
failure more likely
Lower wind speed due to
shorter structure
12/19/2017
30
Con….
12/19/2017
31
Description of a double-fed WTG
12/19/2017
32
1. Blade
2.Pitch Drive
3.Hub
4.Generator rotor
5.Generator stator
6.Yaw drive
7.Wind sensors
8.Service hoist
9.Top Box
10.Main frame
11.Nacelle cover
12.Tower
Nacelle
12/19/2017
33
12/19/2017
34
Wind Farms
Cities and countries need huge wind farms to satisfy
their energy needs.
To optimize energy production in a wind farm,
Turbines are spread 5 – 9 rotor diameter apart in the
prevailing wind direction and,
3 – 5 rotor diameter apart in perpendicular direction
12/19/2017
35
Cont.….
12/19/2017
36
Wind Turbine Control
In general, wind turbines are designed to
operate when the incident wind is high enough
to generate electricity and to shut down when
the wind speed exceeds 25 to 30 m/s.
12/19/2017
37
Yaw Control
The yaw control continuously orients the rotor
in the direction of the wind.
It can be as simple as the tail vane or
More complex on modern towers, using wind
direction sensor and electric or hydraulic drive
motors, to orient the rotor 12/19/2017
38
speed Control
The speed control methods fall into the
following categories.
No speed control: here the wind systems are
designed to withstand the extreme wind speed.
Yaw and tilt control: here the rotor axis is shifted out
of the wind direction when wind speed exceeds the
design limit.
12/19/2017
39
Cont.….
Pitch control: it changes the pitch of the blade with
the changing wind speed to regulate the rotor
speed.
Stall control: here when the wind speed exceeds the
safe limit on the system, the blades are shifted into
a position such that they stall.
12/19/2017
40
Advantage vs dis advantage
Doesn’t produce hazardous wastes.
Use less space than traditional power stations.
Arguments against include fears of damages
From collapsing turbines
Noise
Unreliable power source
A less attractive skyline
Unnecessary high bird fatality
12/19/2017
41
Thank you!
12/19/2017
42
Thank you

Wind energy

  • 1.
  • 2.
    WIND POWER –WHAT IS IT? All renewable energy (except tidal and geothermal power), ultimately comes from the sun. The earth receives 350 W/m2 from the sun. About 2% of this energy (= 7 W/m2) is converted to wind energy. 12/19/2017 2
  • 3.
    WIND POWER –WHAT IS IT? Cont.... Differential heating of the earths surface and atmosphere induces vertical and horizontal air currents that are affected by the earth’s rotation and contours of the land. 12/19/2017 3
  • 4.
    Uneven heating: Intensity ofsolar energy is varies due to the angle of the sun (the equator vs the poles). Land heats up faster than water does, but also loses heat faster. These difference in air temperature across the globe can create wind. 12/19/2017 4
  • 5.
    Uneven heating: Con…. 35%of wind energy (2.45 W/m2) is dissipated in the first kilometers above the Earth’s surface and available for turbine. 12/19/2017 5
  • 6.
    Available power: Over aperiod of one year, the wind energy (E) is approximately. 𝐸 = 𝑖𝑛𝑡𝑒𝑛𝑠𝑖𝑡𝑦 ∗ 𝐸𝑎𝑟𝑡ℎ′ 𝑠 𝑆𝐴 ∗ 𝑆𝑒𝑐𝑜𝑛𝑑𝑠 𝑝𝑒𝑟 𝑦𝑒𝑎𝑟 = 2.45 𝑊/𝑚2 5.1 𝑥 1014 𝑚2 3.2 𝑥 107 𝑠 = 4.0 𝑥 1022 𝐽 Which is 200 times larger than our energy consumption (2.0 𝑥 1020 𝐽). 12/19/2017 6
  • 7.
    Maximum Power Extracted Calculatethe power extracted from wind. Calculate kinetic energy, 𝐾𝐸 = 1 2 𝑚𝑣2 of air passing through the rotor of the wind turbine. Measure mass of the air travelling through area of circle swept out by rotor blades in time ∆𝑡. 12/19/2017 7
  • 8.
    Con…. Time t =0: Time ∆𝑡: 𝑣. ∆𝑡 Figure 1: At time t=0, mass of air is just about to pass through the loop, but ∆𝑡 later, the mass of air is passed through the loop. The mass of this piece of air is the product of its density 𝜌, area A, and length 𝑣. ∆𝑡. A 12/19/2017 8
  • 9.
    Con…. From this youcan find the mass. M𝑎𝑠𝑠 = 𝑑𝑒𝑛𝑠𝑖𝑡𝑦 ∗ 𝑣𝑜𝑙𝑢𝑚𝑒 = 𝜌 ∗ 𝐴 ∗ 𝑣 ∗ ∆𝑡 𝑣 𝑖𝑠 𝑡ℎ𝑒 𝑣𝑒𝑙𝑜𝑐𝑖𝑡𝑦 𝑜𝑓 𝑎𝑖𝑟 𝜌 𝑖𝑠 𝑑𝑒𝑛𝑠𝑖𝑡𝑦 𝑜𝑓 𝑎𝑖𝑟 1.23 𝑓𝑜𝑟 𝑠𝑡𝑎𝑛𝑑𝑎𝑟𝑑 𝑇 𝑎𝑛𝑑 𝑃 ∆𝑡 𝑖𝑠 𝑙𝑒𝑛𝑔𝑡ℎ 𝑜𝑓 𝑡𝑖𝑚𝑒 𝑓𝑜𝑟 𝑎 𝑢𝑛𝑖𝑡 𝑎𝑖𝑟 𝑡𝑜 𝑝𝑎𝑠𝑠 𝑡ℎ𝑟𝑜𝑢𝑔ℎ 𝐴 𝑖𝑠 𝑎𝑟𝑒𝑎 𝑠𝑤𝑒𝑝𝑡 𝑏𝑦 𝑡ℎ𝑒 𝑏𝑙𝑎𝑑𝑒𝑠, 𝑛𝑜𝑡 𝑡ℎ𝑒 𝑏𝑙𝑎𝑑𝑒 𝑎𝑟𝑒𝑎 12/19/2017 9
  • 10.
    Con…. Therefore the kineticenergy, KE, is found to be. 𝐾𝐸 = 1 2 𝑚𝑣2 = 1 2 𝜌𝐴∆𝑡𝑣3 While the power of the wind passing through the loop is. 𝑃 = 1 2 𝜌𝐴∆𝑡𝑣3 ∆𝑡 = 𝟏 𝟐 𝝆𝑨𝒗 𝟑 12/19/2017 10
  • 11.
    Con…. But turbines can’textract all of the kinetic energy of the wind. Why not? The above expression is true for a single wind turbine in constant wind condition. 12/19/2017 11
  • 12.
    Actual Power Extractedfrom the Wind The actual power extracted by the rotor blades is the difference between the upstream and the downstream wind powers. 𝑃 𝑜 = 1 2 𝑚𝑎𝑠𝑠 𝑓𝑙𝑜𝑤 𝑟𝑎𝑡𝑒 𝑝𝑒𝑟 𝑠𝑒𝑐𝑜𝑛𝑑 . (𝑉2 − 𝑉𝑜 2 ) 𝑉 = 𝑢𝑝𝑠𝑡𝑟𝑒𝑎𝑚 𝑤𝑖𝑛𝑑 𝑣𝑒𝑙𝑜𝑐𝑖𝑡𝑦 𝑉𝑜= 𝑑𝑜𝑤𝑛𝑠𝑡𝑟𝑒𝑎𝑚 𝑤𝑖𝑛𝑑 𝑣𝑒𝑙𝑜𝑐𝑖𝑡𝑦 𝑃𝑜 = 𝑚𝑐ℎ𝑎𝑛𝑖𝑐𝑎𝑙 𝑝𝑜𝑤𝑒𝑟 𝑜𝑢𝑡𝑝𝑢𝑡 12/19/2017 12
  • 13.
    Con…. The mass flowrate of air through the rotating blades is, therefore, derived by multiplying the density with the average velocity. That is M𝑎𝑠𝑠 𝑓𝑙𝑜𝑤 𝑟𝑎𝑡𝑒 = 𝜌. 𝐴. 𝑉 + 𝑉𝑜 2 12/19/2017 13
  • 14.
    Con…. The mechanical powerextracted by the rotor, which is driving the electrical generator is therefore: 𝑃𝑜 = 1 2 𝜌. 𝐴. 𝑉 + 𝑉𝑜 2 . (𝑉2 − 𝑉𝑜 2 ) 12/19/2017 14
  • 15.
    Con…. The above expressioncan be algebraically rearranged: 𝑃𝑜 = 1 2 𝜌. 𝐴. 𝑉3 . 1 + 𝑉𝑜 𝑉 1 − 𝑉𝑜 𝑉 2 2 12/19/2017 15
  • 16.
    Con…. The power extractedby the blade is customarily expressed as a fraction of the upstream wind power as follows: 𝑃𝑜 = 1 2 𝜌. 𝐴. 𝑉3 . 𝐶 𝑝 where 𝐶 𝑝 = 1 + 𝑉𝑜 𝑉 1 − 𝑉𝑜 𝑉 2 2 12/19/2017 16
  • 17.
    Con…. For a givenupstream wind speed, the value of Cp depends on the ratio of the downstream to the upstream wind speeds that is 𝑉𝑜 𝑉 . The plot of power coefficient versus ( 𝑉𝑜 𝑉 ) shows that Cp is a single, maximum value function 12/19/2017 17
  • 18.
    Con…. It has amaximum value of 0.59 (Betz limit) when the ( 𝑉𝑜 𝑉) is one-third (0.33). The maximum power is extracted from the wind at speed ratio, when the downstream wind speed equals one-third of the upstream speed. 𝑃𝑚𝑎𝑥 = 1 2 𝜌. 𝐴. 𝑉3 . 0.59 12/19/2017 18
  • 19.
    Con…. The theoretical maximumvalue of Cp is 0.59. in practical designs, the maximum achievable Cp is below 0.5. 12/19/2017 19
  • 20.
    Efficiency Wind turbines arenot 100% efficient. Power = efficiency * max. power extracted 𝑃𝑜 = 𝜂 1 2 𝜌. 𝐴. 𝑉3 = 𝜂 1 2 𝜌. 𝑉3 . 𝜋 𝑑 2 2 = 1 8 𝜂. 𝜌. 𝑉3 . 𝜋𝑑2 12/19/2017 20
  • 21.
    Factor affecting windpower harnessing The power produced by a wind turbine depends on: Rotor area Air density Wind speed Wind shear 12/19/2017 21
  • 22.
    Con…. Wind shear isa difference in wind speed and direction over a short distance and is caused by mountains, coastline, and weather pattern. Air density increases with colder temperatures, decreased with altitude, and decreased humidity Wind speed increases the farther you get away from ground. 12/19/2017 22
  • 23.
    Con…. As you gethigher off the ground, the air speed increases. The rotor are tilted slightly upwards so that each part of the rotor is exposed to the same speed 12/19/2017 23
  • 24.
    Con…. Wind turbines aremost efficient when wind moves uniformly in the same direction. Turbulence is caused by buildings, trees, and land formations (wind break). The edge of a continental shelf, high ground and tundra have low turbulence and are the best locations to build a turbine 12/19/2017 24
  • 25.
    Feasibility Local wind speedis also an important factor since power ∝ (𝑤𝑖𝑛𝑑 𝑠𝑝𝑒𝑒𝑑)3 . The local wind speed should be, on average, at least 7 m/s at 25 m above the earth’s surface in order to make harnessing wind from it worthwhile. 12/19/2017 25
  • 26.
    Demand and Dependability Windis not locally predictable in the short term, and so its use should be limited to only fulfill 5- 15% of the total energy demand of the area. Setting up turbines in several locations makes wind energy more reliable. 12/19/2017 26
  • 27.
    Con…. The available poweris averaged. Globally there is always a relatively constant amount of wind energy being harnessed at any one moment. 12/19/2017 27
  • 28.
    Configuration of WindTurbine 12/19/2017 28
  • 29.
    HAWT’s vs VAWT’s HAWT’s Advantage Variablepitch Tall tower- higher wind speeds Steady angle attack Disadvantage Tall tower/large blade- difficult to install High visibility Yaw control is necessary 12/19/2017 29
  • 30.
    HAWT’s vs VAWT’scont.… VAWT’s Advantage Smaller support structure Yaw control not needed Generator components located on the ground Less noise compared to HAWT’s Disadvantage Cyclic loading makes fatigue failure more likely Lower wind speed due to shorter structure 12/19/2017 30
  • 31.
  • 32.
    Description of adouble-fed WTG 12/19/2017 32
  • 33.
    1. Blade 2.Pitch Drive 3.Hub 4.Generatorrotor 5.Generator stator 6.Yaw drive 7.Wind sensors 8.Service hoist 9.Top Box 10.Main frame 11.Nacelle cover 12.Tower Nacelle 12/19/2017 33
  • 34.
  • 35.
    Wind Farms Cities andcountries need huge wind farms to satisfy their energy needs. To optimize energy production in a wind farm, Turbines are spread 5 – 9 rotor diameter apart in the prevailing wind direction and, 3 – 5 rotor diameter apart in perpendicular direction 12/19/2017 35
  • 36.
  • 37.
    Wind Turbine Control Ingeneral, wind turbines are designed to operate when the incident wind is high enough to generate electricity and to shut down when the wind speed exceeds 25 to 30 m/s. 12/19/2017 37
  • 38.
    Yaw Control The yawcontrol continuously orients the rotor in the direction of the wind. It can be as simple as the tail vane or More complex on modern towers, using wind direction sensor and electric or hydraulic drive motors, to orient the rotor 12/19/2017 38
  • 39.
    speed Control The speedcontrol methods fall into the following categories. No speed control: here the wind systems are designed to withstand the extreme wind speed. Yaw and tilt control: here the rotor axis is shifted out of the wind direction when wind speed exceeds the design limit. 12/19/2017 39
  • 40.
    Cont.…. Pitch control: itchanges the pitch of the blade with the changing wind speed to regulate the rotor speed. Stall control: here when the wind speed exceeds the safe limit on the system, the blades are shifted into a position such that they stall. 12/19/2017 40
  • 41.
    Advantage vs disadvantage Doesn’t produce hazardous wastes. Use less space than traditional power stations. Arguments against include fears of damages From collapsing turbines Noise Unreliable power source A less attractive skyline Unnecessary high bird fatality 12/19/2017 41
  • 42.