Lect8

Lect8

• 1.
  Decision Making inJava •if statement •else if statement •If else if statement •Nested if statements •Switch Statement 4/10/2019 1Jamsher Bhanbhro(F16CS11)
• 2.
  Decision Making • Indecision making there are one or more conditions to be checked during the execution of a program. • The decision depends upon our conditions as it may return true or false result. 4/10/2019 Jamsher Bhanbhro(F16CS11) 2
• 3.
  If statement If statementis used to check one or more Boolean conditions to execute a block of statements or code. • Syntax: if(Boolean Statements){//code body to be executed if the statement is true} E.g: if(a>11){ System.out.println(“Your Condition is true”);} 4/10/2019 Jamsher Bhanbhro(F16CS11) 3
• 4.
  If else statement •An if statement can be followed by the else statement if statement will be executed when your condition is true and in the case of the else statement it will be executed when if’s condition will be false. • I.E: int a=3; if(a>2){ System.out.println(“If is true”);} else{ System.out.println(“If is false”);} 4/10/2019 Jamsher Bhanbhro(F16CS11) 4
• 5.
  If else ifstatement • An if statement is followed by an optional else if statement. • One else if statement is correct than all followed statements will not be executed. • If(Bool Cond){}else if(cond){}else if(cond){}…… int a=11; If(a<11){} else if(a<9){}… 4/10/2019 Jamsher Bhanbhro(F16CS11) 5
• 6.
  Nested If • Itmeans we can use if or else if inside the if statement. • Than all conditions will be executed sequentially. • If(Bool Cond){if(bool cond){}}…. 4/10/2019 Jamsher Bhanbhro(F16CS11) 6
• 7.
  Switch Statement • Avalue to be sated in a variable. • And on that value conditions will be checked accordingly. • Each value is called case, variables can be integer type, char type or Boolean type. • Understand syntax of the Switch statement in the following program I.E: int a; Switch(a){ case ‘1’: System.out.println(“Jamsher”);} break; case’2’: ….} 4/10/2019 Jamsher Bhanbhro(F16CS11) 7
• 8.
  Why Decision makingis used in programming? 4/10/2019 Jamsher Bhanbhro(F16CS11) 8
• 9.
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