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Basic structure of computers | PPT
Chapter 1. Basic
Structure of Computers
Functional Units
Functional Units
Arithmetic
and
logic

Input
Memory
Output

Control

I/O

Processor

Figure 1.1.  Basic functional units of a computer.
Information Handled by a
Computer
 Instructions/machine




instructions

Govern the transfer of information within a computer as
well as between the computer and its I/O devices
Specify the arithmetic and logic operations to be
performed
Program

 Data



Used as operands by the instructions
Source program

 Encoded

in binary code – 0 and 1
Memory Unit
 Store

programs and data
 Two classes of storage


Primary storage





Fast
Programs must be stored in memory while they are being executed
Large number of semiconductor storage cells
Processed in words
Address
RAM and memory access time
Memory hierarchy – cache, main memory



Secondary storage – larger and cheaper






Arithmetic and Logic Unit
(ALU)
 Most

computer operations are executed in
ALU of the processor.
 Load the operands into memory – bring them
to the processor – perform operation in ALU –
store the result back to memory or retain in
the processor.
 Registers
 Fast control of ALU
Control Unit









All computer operations are controlled by the control
unit.
The timing signals that govern the I/O transfers are
also generated by the control unit.
Control unit is usually distributed throughout the
machine instead of standing alone.
Operations of a computer:
Accept information in the form of programs and data through an
input unit and store it in the memory
Fetch the information stored in the memory, under program control,
into an ALU, where the information is processed
Output the processed information through an output unit
Control all activities inside the machine through a control unit
The processor : Data Path and
Control

Two types of functional units:
elements that operate on data values (combinational)
 elements that contain state (state elements)
Five Execution Steps
Step name

Action for R-type
instructions

Action for Memoryreference Instructions

Action for
branches

Instruction fetch

IR = MEM[PC]
PC = PC + 4

Instruction decode/ register
fetch

Action for
jumps

A = Reg[IR[25-21]]
B = Reg[IR[20-16]]
ALUOut = PC + (sign extend (IR[15-0])<<2)

Execution, address
computation, branch/jump
completion

ALUOut = A op B

ALUOut = A+sign
extend(IR[15-0])

Memory access or R-type
completion

Reg[IR[15-11]] =
ALUOut

Load:MDR =Mem[ALUOut]
or
Store:Mem[ALUOut] = B

Memory read completion

Load: Reg[IR[20-16]] =
MDR

IF(A==B) Then
PC=ALUOut

PC=PC[3128]||(IR[250]<<2)
Review







Activity in a computer is governed by instructions.
To perform a task, an appropriate program
consisting of a list of instructions is stored in the
memory.
Individual instructions are brought from the memory
into the processor, which executes the specified
operations.
Data to be used as operands are also stored in the
memory.
A Typical Instruction







Add LOCA, R0
Add the operand at memory location LOCA to the
operand in a register R0 in the processor.
Place the sum into register R0.
The original contents of LOCA are preserved.
The original contents of R0 is overwritten.
Instruction is fetched from the memory into the
processor – the operand at LOCA is fetched and
added to the contents of R0 – the resulting sum is
stored in register R0.
Separate Memory Access and
ALU Operation
 Load

LOCA, R1
 Add R1, R0
 Whose contents will be overwritten?
Connection Between the
Processor and the Memory
Memory

MAR

MDR
Control

PC

R0
R1

Processor

IR
ALU
Rn ­

1

n general purpose
registers

Figure 1.2.   Connections between the processor and the  memory.
Registers
 Instruction

register (IR)
 Program counter (PC)
 General-purpose register (R – R )
0
n-1
 Memory

address register (MAR)
 Memory data register (MDR)
Typical Operating Steps
 Programs

reside in the memory through input

devices
 PC is set to point to the first instruction
 The contents of PC are transferred to MAR
 A Read signal is sent to the memory
 The first instruction is read out and loaded
into MDR
 The contents of MDR are transferred to IR
 Decode and execute the instruction
Typical Operating Steps
(Cont’)
 Get



operands for ALU

General-purpose register
Memory (address to MAR – Read – MDR to ALU)

 Perform

operation in ALU
 Store the result back



To general-purpose register
To memory (address to MAR, result to MDR – Write)

 During

the execution, PC is
incremented to the next instruction
Interrupt







Normal execution of programs may be preempted if
some device requires urgent servicing.
The normal execution of the current program must
be interrupted – the device raises an interrupt
signal.
Interrupt-service routine
Current system information backup and restore (PC,
general-purpose registers, control information,
specific information)
Bus Structures
 There

are many ways to connect different
parts inside a computer together.
 A group of lines that serves as a connecting
path for several devices is called a bus.
 Address/data/control
Bus Structure
 Single-bus

Input

Output

Memory

Figure 1.3.    Single­bus structure.

Processor
Speed Issue
 Different

devices have different
transfer/operate speed.
 If the speed of bus is bounded by the slowest
device connected to it, the efficiency will be
very low.
 How to solve this?
 A common approach – use buffers.
Performance
Performance
 The

most important measure of a computer is
how quickly it can execute programs.
 Three factors affect performance:




Hardware design
Instruction set
Compiler
Performance


Processor time to execute a program depends on the hardware
involved in the execution of individual machine instructions.
Main
memory

Cache
memory

Processor

Bus

Figure 1.5.

The processor cache.
Performance
 The

processor and a relatively small cache
memory can be fabricated on a single
integrated circuit chip.
 Speed
 Cost
 Memory management
Processor Clock
 Clock,

clock cycle, and clock rate
 The execution of each instruction is divided
into several steps, each of which completes
in one clock cycle.
 Hertz – cycles per second
Basic Performance Equation






T – processor time required to execute a program that has been
prepared in high-level language
N – number of actual machine language instructions needed to
complete the execution (note: loop)
S – average number of basic steps needed to execute one
machine instruction. Each step completes in one clock cycle
R – clock rate
Note: these are not independent to each other

N×S
T=
R
How to improve T?
Pipeline and Superscalar
Operation







Instructions are not necessarily executed one after
another.
The value of S doesn’t have to be the number of
clock cycles to execute one instruction.
Pipelining – overlapping the execution of successive
instructions.
Add R1, R2, R3
Superscalar operation – multiple instruction
pipelines are implemented in the processor.
Goal – reduce S (could become <1!)
Clock Rate
 Increase



clock rate

Improve the integrated-circuit (IC) technology to make
the circuits faster
Reduce the amount of processing done in one basic step
(however, this may increase the number of basic steps
needed)

 Increases

in R that are entirely caused by
improvements in IC technology affect all
aspects of the processor’s operation equally
except the time to access the main memory.
CISC and RISC
 Tradeoff

between N and S
 A key consideration is the use of pipelining




S is close to 1 even though the number of basic steps
per instruction may be considerably larger
It is much easier to implement efficient pipelining in
processor with simple instruction sets

 Reduced

Instruction Set Computers (RISC)
 Complex Instruction Set Computers (CISC)
Compiler







A compiler translates a high-level language program
into a sequence of machine instructions.
To reduce N, we need a suitable machine instruction
set and a compiler that makes good use of it.
Goal – reduce N×S
A compiler may not be designed for a specific
processor; however, a high-quality compiler is
usually designed for, and with, a specific processor.
Performance Measurement







T is difficult to compute.
Measure computer performance using benchmark programs.
System Performance Evaluation Corporation (SPEC) selects and
publishes representative application programs for different application
domains, together with test results for many commercially available
computers.
Compile and run (no simulation)
Reference computer

Running time on the reference computer
SPEC rating =
Running time on the computer under test
n

SPEC rating = (∏SPECi )
i =1

1
n
Multiprocessors and
Multicomputers


Multiprocessor computer





Execute a number of different application tasks in parallel
Execute subtasks of a single large task in parallel
All processors have access to all of the memory – shared-memory
multiprocessor
Cost – processors, memory units, complex interconnection networks



Multicomputers



Each computer only have access to its own memory
Exchange message via a communication network – messagepassing multicomputers






Basic structure of computers

  • 1.
  • 2.
  • 3.
  • 4.
    Information Handled bya Computer  Instructions/machine    instructions Govern the transfer of information within a computer as well as between the computer and its I/O devices Specify the arithmetic and logic operations to be performed Program  Data   Used as operands by the instructions Source program  Encoded in binary code – 0 and 1
  • 5.
    Memory Unit  Store programsand data  Two classes of storage  Primary storage   Fast Programs must be stored in memory while they are being executed Large number of semiconductor storage cells Processed in words Address RAM and memory access time Memory hierarchy – cache, main memory  Secondary storage – larger and cheaper     
  • 6.
    Arithmetic and LogicUnit (ALU)  Most computer operations are executed in ALU of the processor.  Load the operands into memory – bring them to the processor – perform operation in ALU – store the result back to memory or retain in the processor.  Registers  Fast control of ALU
  • 7.
    Control Unit         All computeroperations are controlled by the control unit. The timing signals that govern the I/O transfers are also generated by the control unit. Control unit is usually distributed throughout the machine instead of standing alone. Operations of a computer: Accept information in the form of programs and data through an input unit and store it in the memory Fetch the information stored in the memory, under program control, into an ALU, where the information is processed Output the processed information through an output unit Control all activities inside the machine through a control unit
  • 8.
    The processor :Data Path and Control Two types of functional units: elements that operate on data values (combinational)  elements that contain state (state elements)
  • 9.
    Five Execution Steps Stepname Action for R-type instructions Action for Memoryreference Instructions Action for branches Instruction fetch IR = MEM[PC] PC = PC + 4 Instruction decode/ register fetch Action for jumps A = Reg[IR[25-21]] B = Reg[IR[20-16]] ALUOut = PC + (sign extend (IR[15-0])<<2) Execution, address computation, branch/jump completion ALUOut = A op B ALUOut = A+sign extend(IR[15-0]) Memory access or R-type completion Reg[IR[15-11]] = ALUOut Load:MDR =Mem[ALUOut] or Store:Mem[ALUOut] = B Memory read completion Load: Reg[IR[20-16]] = MDR IF(A==B) Then PC=ALUOut PC=PC[3128]||(IR[250]<<2)
  • 10.
    Review     Activity in acomputer is governed by instructions. To perform a task, an appropriate program consisting of a list of instructions is stored in the memory. Individual instructions are brought from the memory into the processor, which executes the specified operations. Data to be used as operands are also stored in the memory.
  • 11.
    A Typical Instruction       AddLOCA, R0 Add the operand at memory location LOCA to the operand in a register R0 in the processor. Place the sum into register R0. The original contents of LOCA are preserved. The original contents of R0 is overwritten. Instruction is fetched from the memory into the processor – the operand at LOCA is fetched and added to the contents of R0 – the resulting sum is stored in register R0.
  • 12.
    Separate Memory Accessand ALU Operation  Load LOCA, R1  Add R1, R0  Whose contents will be overwritten?
  • 13.
    Connection Between the Processorand the Memory Memory MAR MDR Control PC R0 R1 Processor IR ALU Rn ­ 1 n general purpose registers Figure 1.2.   Connections between the processor and the  memory.
  • 14.
    Registers  Instruction register (IR) Program counter (PC)  General-purpose register (R – R ) 0 n-1  Memory address register (MAR)  Memory data register (MDR)
  • 15.
    Typical Operating Steps Programs reside in the memory through input devices  PC is set to point to the first instruction  The contents of PC are transferred to MAR  A Read signal is sent to the memory  The first instruction is read out and loaded into MDR  The contents of MDR are transferred to IR  Decode and execute the instruction
  • 16.
    Typical Operating Steps (Cont’) Get   operands for ALU General-purpose register Memory (address to MAR – Read – MDR to ALU)  Perform operation in ALU  Store the result back   To general-purpose register To memory (address to MAR, result to MDR – Write)  During the execution, PC is incremented to the next instruction
  • 17.
    Interrupt     Normal execution ofprograms may be preempted if some device requires urgent servicing. The normal execution of the current program must be interrupted – the device raises an interrupt signal. Interrupt-service routine Current system information backup and restore (PC, general-purpose registers, control information, specific information)
  • 18.
    Bus Structures  There aremany ways to connect different parts inside a computer together.  A group of lines that serves as a connecting path for several devices is called a bus.  Address/data/control
  • 19.
  • 20.
    Speed Issue  Different deviceshave different transfer/operate speed.  If the speed of bus is bounded by the slowest device connected to it, the efficiency will be very low.  How to solve this?  A common approach – use buffers.
  • 21.
  • 22.
    Performance  The most importantmeasure of a computer is how quickly it can execute programs.  Three factors affect performance:    Hardware design Instruction set Compiler
  • 23.
    Performance  Processor time toexecute a program depends on the hardware involved in the execution of individual machine instructions. Main memory Cache memory Processor Bus Figure 1.5. The processor cache.
  • 24.
    Performance  The processor anda relatively small cache memory can be fabricated on a single integrated circuit chip.  Speed  Cost  Memory management
  • 25.
    Processor Clock  Clock, clockcycle, and clock rate  The execution of each instruction is divided into several steps, each of which completes in one clock cycle.  Hertz – cycles per second
  • 26.
    Basic Performance Equation      T– processor time required to execute a program that has been prepared in high-level language N – number of actual machine language instructions needed to complete the execution (note: loop) S – average number of basic steps needed to execute one machine instruction. Each step completes in one clock cycle R – clock rate Note: these are not independent to each other N×S T= R How to improve T?
  • 27.
    Pipeline and Superscalar Operation       Instructionsare not necessarily executed one after another. The value of S doesn’t have to be the number of clock cycles to execute one instruction. Pipelining – overlapping the execution of successive instructions. Add R1, R2, R3 Superscalar operation – multiple instruction pipelines are implemented in the processor. Goal – reduce S (could become <1!)
  • 28.
    Clock Rate  Increase   clockrate Improve the integrated-circuit (IC) technology to make the circuits faster Reduce the amount of processing done in one basic step (however, this may increase the number of basic steps needed)  Increases in R that are entirely caused by improvements in IC technology affect all aspects of the processor’s operation equally except the time to access the main memory.
  • 29.
    CISC and RISC Tradeoff between N and S  A key consideration is the use of pipelining   S is close to 1 even though the number of basic steps per instruction may be considerably larger It is much easier to implement efficient pipelining in processor with simple instruction sets  Reduced Instruction Set Computers (RISC)  Complex Instruction Set Computers (CISC)
  • 30.
    Compiler     A compiler translatesa high-level language program into a sequence of machine instructions. To reduce N, we need a suitable machine instruction set and a compiler that makes good use of it. Goal – reduce N×S A compiler may not be designed for a specific processor; however, a high-quality compiler is usually designed for, and with, a specific processor.
  • 31.
    Performance Measurement      T isdifficult to compute. Measure computer performance using benchmark programs. System Performance Evaluation Corporation (SPEC) selects and publishes representative application programs for different application domains, together with test results for many commercially available computers. Compile and run (no simulation) Reference computer Running time on the reference computer SPEC rating = Running time on the computer under test n SPEC rating = (∏SPECi ) i =1 1 n
  • 32.
    Multiprocessors and Multicomputers  Multiprocessor computer   Executea number of different application tasks in parallel Execute subtasks of a single large task in parallel All processors have access to all of the memory – shared-memory multiprocessor Cost – processors, memory units, complex interconnection networks  Multicomputers  Each computer only have access to its own memory Exchange message via a communication network – messagepassing multicomputers   