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![Introduction
T [1 . . n] : Text of length n.
P [1 . . m] : Pattern of length m.
∑ : A Finite Alphabet consisting of characters from which the elements of
P and T are drawn.
Eg.: ∑ = {0, 1}
∑ = {a, b, . . . , z}
String-Matching Problem:
Find All Valid Shifts with which a given Pattern P occurs in a given Text T.
Strings of Characters](https://image.slidesharecdn.com/naivestringmatchingalgorithm-200422174013/85/Naive-string-matching-algorithm-2-320.jpg)
![Introduction…
Shift (s): A Pattern P is said to occur with shift s in text T, if 0 ≤ s ≤ n – m and
T [s + 1 . . s + m] = P [1 . . m]. (T [s + j] = P [j] for 1 ≤ j ≤ m)
P occurs beginning at position s + 1 in text T.
• Valid Shift: P occurs with shift s in T.
• Invalid Shift: P does not occur in T.
String-matching algorithms generally perform some Preprocessing based on the pattern and
then finds all Valid Shifts (Matching).](https://image.slidesharecdn.com/naivestringmatchingalgorithm-200422174013/85/Naive-string-matching-algorithm-3-320.jpg)
![Algorithm
Finds All Valid Shifts using a loop that checks the condition:
P [1 . . m] = T [s + 1 . . s + m] for each of the n – m + 1 possible values of s.
NAIVE-STRING-MATCHER (T, P)
n = T.length
l = P.length
For (s = 0 to n – m)
If (P [1 . . m] = T [s + 1 . . s + m])
Print “Pattern occurs with shift s”
Running Time:
Worst Case: Ө ((n – m + 1) m)
Best Case: Ө (n + m)](https://image.slidesharecdn.com/naivestringmatchingalgorithm-200422174013/85/Naive-string-matching-algorithm-4-320.jpg)
![Introduction
T [1 . . n] : Text of length n.
P [1 . . m] : Pattern of length m.
∑ : A Finite Alphabet consisting of characters from which the elements of
P and T are drawn.
Eg.: ∑ = {0, 1}
∑ = {a, b, . . . , z}
String-Matching Problem:
Find All Valid Shifts with which a given Pattern P occurs in a given Text T.
Strings of Characters](https://image.slidesharecdn.com/naivestringmatchingalgorithm-200422174013/75/Naive-string-matching-algorithm-2-2048.jpg)
![Introduction…
Shift (s): A Pattern P is said to occur with shift s in text T, if 0 ≤ s ≤ n – m and
T [s + 1 . . s + m] = P [1 . . m]. (T [s + j] = P [j] for 1 ≤ j ≤ m)
P occurs beginning at position s + 1 in text T.
• Valid Shift: P occurs with shift s in T.
• Invalid Shift: P does not occur in T.
String-matching algorithms generally perform some Preprocessing based on the pattern and
then finds all Valid Shifts (Matching).](https://image.slidesharecdn.com/naivestringmatchingalgorithm-200422174013/75/Naive-string-matching-algorithm-3-2048.jpg)
![Algorithm
Finds All Valid Shifts using a loop that checks the condition:
P [1 . . m] = T [s + 1 . . s + m] for each of the n – m + 1 possible values of s.
NAIVE-STRING-MATCHER (T, P)
n = T.length
l = P.length
For (s = 0 to n – m)
If (P [1 . . m] = T [s + 1 . . s + m])
Print “Pattern occurs with shift s”
Running Time:
Worst Case: Ө ((n – m + 1) m)
Best Case: Ө (n + m)](https://image.slidesharecdn.com/naivestringmatchingalgorithm-200422174013/75/Naive-string-matching-algorithm-4-2048.jpg)
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Naive string matching algorithm
- 1. Naïve String MatchingAlgorithm Dr. Kiran K Assistant Professor Department of CSE UVCE Bengaluru, India.
- 2. Introduction T [1 .. n] : Text of length n. P [1 . . m] : Pattern of length m. ∑ : A Finite Alphabet consisting of characters from which the elements of P and T are drawn. Eg.: ∑ = {0, 1} ∑ = {a, b, . . . , z} String-Matching Problem: Find All Valid Shifts with which a given Pattern P occurs in a given Text T. Strings of Characters
- 3. Introduction… Shift (s): APattern P is said to occur with shift s in text T, if 0 ≤ s ≤ n – m and T [s + 1 . . s + m] = P [1 . . m]. (T [s + j] = P [j] for 1 ≤ j ≤ m) P occurs beginning at position s + 1 in text T. • Valid Shift: P occurs with shift s in T. • Invalid Shift: P does not occur in T. String-matching algorithms generally perform some Preprocessing based on the pattern and then finds all Valid Shifts (Matching).
- 4. Algorithm Finds All ValidShifts using a loop that checks the condition: P [1 . . m] = T [s + 1 . . s + m] for each of the n – m + 1 possible values of s. NAIVE-STRING-MATCHER (T, P) n = T.length l = P.length For (s = 0 to n – m) If (P [1 . . m] = T [s + 1 . . s + m]) Print “Pattern occurs with shift s” Running Time: Worst Case: Ө ((n – m + 1) m) Best Case: Ө (n + m)
- 5. References: • Thomas HCormen. Charles E Leiserson, Ronald L Rivest, Clifford Stein, Introduction to Algorithms, Third Edition, The MIT Press Cambridge, Massachusetts London, England.